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x^2/(x+2)=625
We move all terms to the left:
x^2/(x+2)-(625)=0
Domain of the equation: (x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
x^2-625*(x+2)=0
We multiply parentheses
x^2-625x-1250=0
a = 1; b = -625; c = -1250;
Δ = b2-4ac
Δ = -6252-4·1·(-1250)
Δ = 395625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{395625}=\sqrt{625*633}=\sqrt{625}*\sqrt{633}=25\sqrt{633}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-625)-25\sqrt{633}}{2*1}=\frac{625-25\sqrt{633}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-625)+25\sqrt{633}}{2*1}=\frac{625+25\sqrt{633}}{2} $
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